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Double Barreled PUMP Shotgun
- Thread starter Cron
- Start date
Is that a screwdriver pulling the triggers?
sodajones
Combat Engineer
burningfeathers
Reading the grout jokes
I had high hopes of badassness when I opened this thread. Alas, I am disapointed. Not impressed :|
You know, since the triggers are independent he can theoretically pull them at the exact same time. That doesn't double recoil, it increases it by a factor of four. That means out of those barrels if he shot a magnum load, he could possibly have recoil loads upwards of 150-180 ft-lbs, if not more. Not exactly ideal for a pistol grip.
Obviously an Aggy Engineering grad student.
Cron
Yankee Uniform Tango
Granted, it looks like shit. That said, I always wanted to see one of these made; maybe this could be the first step towards someone actually making a legit one.
How does it increase it by a factor of 4?
I was wondering that too.
Also, since it's twice as heavy, wouldn't that help a bit with how it feels (even though the force is more, the acceleration should be the same maybe? Been a while since physics).
Also I think he left the stock on one of the guns, if you look closely.
What a waste of two perfectly good shotguns.
**Nerd alert warning**
If the triggers were pulled at exactly the same time, you double everything coming out of barrels...gas, unburnt powder, shot, and the velocity also doubles (not for each barrel, for the total sum).
Two commonly accepted equations for shotgun recoil are
Vg =(Ws + Ww + 1.5Wp) Vm / 7000 Wg
Eg =( Wg * Vg^2 ) / 2g
Where
g = gun
s = shot in grains
w= wad in grains
p= powder in grains
E= energy in foot pounds
m= muzzle
V= velocity in f.p.s.
W= weight
So, if you run those equations for a 3 inch, 12 gauge shell with a 1 3/4 shot charge, you'll get an approximate recoil of about 55 ft-lbs. If you double the velocity though, you'll see in the equation that results in a factor of 4, so the total recoil is actually about 220 ft-lbs.
Yes, it will help with how it feels on your shoulder, but that only changes perceived recoil, the total is still roughly the same.
So, I definitely would not be a fan of holding that thing by the pistol grip and doubling the shotgun. That would suck.
Free Recoil = 0.5 • (mbullet • vbullet + mpowder • vpowder) ² / (mgun)
I don't see it either. It's perfectly valid to just add the free recoil of both guns together, since there are no synergistic effects that are immediately apparent. Since both guns are the same w/ the same round, calculate for one gun and multiply by two.
EDIT: Ah, did you distribute a x2 inside the parentheses, which are squared, and pull it out as a x4? You have to remember to divide out by twice the weight of the gun, too, which makes the 4 a 2.
What's that aggy?
Tell you what, when all of you corps turds stop calling The University of Texas "TU", I'll stop calling your retarded wanna-be GI Joe boy's club "aggy".
Deal?