Ok, so after getting home I realize my argument is invalid for the doubling of the muzzle velocity. My apologies to all, after reading my notes my memory apparently isn't as good as I thought, I was confusing muzzle velocity with recoil velocity. Prop and MB, you guys are right about the muzzle velocity with a gross conceptual error on my part.
However, what velocity I
should have been talking about was the recoil velocity, which will double as the barrels of the shotgun are fired at exactly the same time.
Here's why. The charge is doubled, which doubles the recoiling velocity of the gun as well as the recoil impulse of the gun, which results in a total increase in free recoil by a factor of four.
The equations notwithstanding I posted earlier, I'm going to use a calculator off of
Handloads.com, because quite honestly I'm not going to fat finger the numbers and don't feel like scanning in handwritten notes. I'm also going to simulate using a double-barrel .308 instead of a shotgun, because these numbers I'm using below are actual numbers I've personally tested and recorded with handloads and a chronograph at the range, not just something made up for the sake of argument.
Load 1
168.2 gr Sierra HPBT
2631 fps bullet velocity
43.5 gr IMR 4064
10 lb M-1 Garand
Recoil Impulse - 2.74 lb-sec
Velocity of Recoiling M-1 - 8.81 fps
Free Recoil - 12.05 ft-lbs
Load 2 (everything is doubled)
336.4 gr Sierra HPBT
2631 fps bullet velocity
87 gr IMR 4064
10 lb M-1 Garand
Recoil Impulse - 5.47 lb-sec
Velocity of Recoiling M-1 - 17.62 fps
Free Recoil - 48.18 ft-lbs
48.18 / 12.05 = 3.99834!!!
So, while I'll readily admit I was retarded about which velocity was being doubled, the fact still remains that the total recoil of a gun that has both barrels shot at the exact same time is increased by a factor of
FOUR and not two