Even if the railgun had a 200nm range, are we going to bring our super awesome CG(X) in to 20nm off a hostile shore to shell a target 180nm inland? Methinketh no.
Why not?
Even if the railgun had a 200nm range, are we going to bring our super awesome CG(X) in to 20nm off a hostile shore to shell a target 180nm inland? Methinketh no.
Drag does not change as objects go supersonic. I care about the final velocity because that is directly proportional to its destructive force. If a railgun shooting a round into space causes the same destructive force as dropping a bullet from a plane, it's not going to do enough to eliminate threats at sea.As far as the terminal velocity argument, who really cares what the final velocity is? Some 200lb heads apparently worked it out and think it works. I don't have the tools to do computer modeling accounting for hypersonic fluid mechanics or the air density variations at the extreme altitudes proposed, do you?
I think you and I have the same concern in this regard. But this also leads to two additional questions:At the very least, a high density object traveling at high speed is going to be a great bunker buster, runway crater-er, etc. My worry would be its NSFS effectiveness compared to traditional artillery, particularly as it has no explosives to provide blast.
Well, it depends on the enemy. If we're up against a significant ASW threat, like the extremely quiet but short ranged AIP plants some of our current allies use and our aging 688 fleet is ill prepared to deal with, then no, you probably won't put the multi-billion dollar DD(X) 20 nm off shore.Why not?
Well, it depends on the enemy. If we're up against a significant ASW threat, like the extremely quiet but short ranged AIP plants some of our current allies use and our aging 688 fleet is ill prepared to deal with, then no, you probably won't put the multi-billion dollar DD(X) 20 nm off shore.
Friggin' nerds ... :sleep_125
Will, you're ignoring friction. You can't just do a direct PE---> KE conversion... that's the whole point of "terminal velocity." There is a point of no returns where friction force = gravitational force, so you don't gain any KE no matter how high the object falls from. All the PE after terminal velocity is being lost to friction.
You can google the equation for terminal velocity. Put in the speed for mach 5 and solve for mass/Area. You will need a really, really large m/A ratio to attain mach 5. Btw, when I said dropping a bullet I meant a likewise sized missile-shaped object...just couldn't call it a bomb because there's no explosives in it.
Spekkio ... you really, really need to find a nice girl and 'settle down' ...whether this post is 'real' or tongue-in-cheek -- doesn't matter ...